Let us consider the nominal mix is 1:2:4
Loss of cement is considered as 2%
Output of mix is considered as 67%
To achieve 1 cum output,
we need 1/0.67 = 1.49 say 1.50 cum dry mix.
Now add the wastage of 2%, i.e (1.50 + 0.02) = 1.52 cum.
Volume of cement = (cement/cement+sand+aggregate) × Total
material =(1/1+2+4) × 1.52
=0.2171 cum
As we know, the density of cement is 1440 kg/cum and
Weight of 1 bag cement = 50 kg.
Therefore volume of 1 bag cement = 50/1440
= 0.0347 cum.
∴ No. of cement bags required in
1 cubic meter =
0.2171/0.0347= 6.25 bags.